A rheostat with a resistance of 100 Ohm is completely inserted into the circuit, the current strength of which is 3A.

A rheostat with a resistance of 100 Ohm is completely inserted into the circuit, the current strength of which is 3A. How much heat will be released in the rheostat within 10 minutes?

Initial data: R (rheostat resistance) = 100 Ohm; I (current in the circuit into which the rheostat was introduced) = 3 A; t (duration of the rheostat in the circuit) = 10 min (60 s).

The amount of heat that will have time to be released on the rheostat in 10 minutes is determined using the Joule-Lenz law: Q = I ^ 2 * R * t.

Calculation: Q = 3 ^ 2 * 100 * 600 = 540,000 J (540 kJ).

Answer: 540 kJ of heat can be released on the rheostat.



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