A rocket launched vertically upward at a speed of 200m / s moves uniformly with an acceleration

A rocket launched vertically upward at a speed of 200m / s moves uniformly with an acceleration q = 10 m / s ^ 2. Determine the maximum height of its rise

V0 = 200 m / s.

V = 0 m / s.

g = 10 m / s2.

hmax -?

Since during the flight the force of air resistance is not taken into account, the rocket moves under the action of gravity with the acceleration of gravity g.

The height of the rocket rise h will be determined by the formula: h = V0 * t – g * t ^ 2/2.

Let us find the ascent time of the rocket t by the formula: t = (V0 – V) / g.

Since the rocket stops at the maximum height hmax, then V = 0 m / s, t = V0 / g.

The maximum lift hmax of the rocket will be determined by the formula: hmax = V0 * V0 / g – g * V0 ^ 2/2 * g ^ 2 = V0 ^ 2 / g – V0 ^ 2/2 * g = V0 ^ 2/2 * g …

hmax = (200 m / s) 2/2 * 10 m / s2 = 2000 m.

Answer: the maximum height of the rocket was hmax = 2000 m.