A roller working on paving on a highway exerts a pressure of 400 kPa on it.

A roller working on paving on a highway exerts a pressure of 400 kPa on it. The area of the roller support is 0.12 m squared. What is the mass of this roller?

Given:

P = 400 kPa = 400000 Pascal – the pressure exerted by the roller on the asphalt;

S = 0.2 m ^ 2 – the area of the roller support;

g = 10 N / kg – acceleration of gravity.

It is required to determine m (kilogram) – the mass of the roller.

Find the force with which the roller presses on the asphalt:

F = P * S = 400,000 * 0.2 = 80,000 Newtons.

This force is equal to the force of gravity acting on the roller. Then:

F = m * g, hence:

m = F / g = 80,000/10 = 8,000 kilograms.

Answer: The weight of the roller is 8000 kilograms (8 tons).