A room with a volume of 150 cubic meters at a temperature of 25 degrees

A room with a volume of 150 cubic meters at a temperature of 25 degrees Celsius contains 2380 grams of water vapor. Determine the relative humidity.

Data: V (room volume) = 150 m3; t (temperature) = 25 ºС; m (mass of water vapor contained in the indicated room) = 2380 g.

Constants: ρp (saturated vapor density) = 23 g / m3.

To find the relative humidity in the specified room, we apply the formula: φ = ρ / ρp = m / (ρp * V).

Let’s make a calculation: φ = m / (ρp * V) = 2380 / (23 * 150) = 0.69 or 69%.

Answer: The relative humidity in the specified room is 69%.