A rubber ball falls from a height of h = 5.0 m. What part n of the potential energy of the ball went to increase the internal

A rubber ball falls from a height of h = 5.0 m. What part n of the potential energy of the ball went to increase the internal energy if after the impact it rose to a height of h1 = 3.0 m?

To calculate how much of the potential energy of the taken ball has passed into the internal one, we apply the formula: η = 1 – En1 / En0 = 1 – m * g * h1 / (m * g * h0) = 1 – h1 / h0.
The values of the variables: h1 – the height to which the taken ball rose after the impact (h1 = 3 m); h0 – initial height (h0 = 5 m).
Let’s make a calculation: η = 1 – h1 / h0 = 1 – 3/5 = 0.4 or 40%.
Answer: The increase in the internal energy of the taken ball took 40% of the initial potential energy.