A rubber cube with an edge of 10 cm is immersed in water. What is the ratio of the volume of a cube under water

A rubber cube with an edge of 10 cm is immersed in water. What is the ratio of the volume of a cube under water to the volume of a cube above the water? The density of rubber is 0.8 g / cm3.

Ft = Fa.

Ft is the force of gravity (Ft = m * g, m is the mass of the cube (m = ρ * V, ρ is the density of the rubber (ρ = 0.8 g / cm³), V is the volume of the cube (V = a³ = 1000 cm3, and Is the edge of the cube (a = 10 cm)))), g is the acceleration of gravity).

Fa is the Archimedes force (Fa = ρw * g * V1, ρw is the density of water (ρw = 1 g / cm³), V1 is the volume of the submerged part).

ρ * V * g = ρw * g * V1.

ρ * V = ρw * V1.

V1 = ρ * V / ρv = 0.8 * 1000/1 = 800 cm3.

V2 (above water) = V – V1 = 1000 – 800 = 200 cm3.

V1 / V2 = 800/200 = 4.



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