A section of a conductor 10 cm long is in a magnetic field with an induction of 50 mT.

A section of a conductor 10 cm long is in a magnetic field with an induction of 50 mT. Ampere force, when the conductor moves 8 cm in the direction of its action, does the work 0.004 J. What is the strength of the current flowing through the conductor? The conductor is perpendicular to the magnetic induction lines.

l = 10 cm = 0.1 m.

B = 50 mT = 0.05 T.

S = 8 cm = 0.08 m.

A = 0.004 J.

I -?

The work of force A is determined by the formula: A = F * S * cosα, where F is the force that acts on the body, S is the movement of the body under the action of the force, ∠α is the angle between F and S.

Since the conductor moves in the direction of the force, then ∠α = 0 °, cos0 ° = 1.

Ampere force F is determined by the formula: F = I * B * l, where I is the current in the conductor, B is the magnetic induction, l is the length of the conductor.

A = I * B * l * S.

I = A / B * l * S.

I = 0.004 J / 0.05 T * 0.1 m * 0.08 m = 10 A.

Answer: the current in the conductor is I = 10 A.