A section of a DNA molecule contains 240 nucleic acid units of guanine, which is 32% of the total.

A section of a DNA molecule contains 240 nucleic acid units of guanine, which is 32% of the total. Determine how many percent and the amount of nuclein content in this part with a value, with temin, with a nucleotide.

Guanine is complementary to cytosine, therefore
G = C = 32% = 240 nucleotides
A + T = 100- (C + G) – according to Chargaff’s rule
Hence
A + T = 36%
A = T = 18% = 240 / 0.32×0.18 = 135 nucleotides



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