A shorted 3 ohm conductor is in a magnetic field. As a result of the change in this field, the magnetic flux piercing

A shorted 3 ohm conductor is in a magnetic field. As a result of the change in this field, the magnetic flux piercing the circuit increased from F1 = 0.002Vb to F2 = 0.005Vb. what charge passed through the cross section of the conductor?

R = 3 ohms. F1 = 0.002 Wb. F2 = 0.005 Wb. Q -? In a conductor, which is in an alternating magnetic field, an electromotive force arises, the phenomenon of electro-magnetic induction occurs. E.D.S. = – ΔФ / t, where ΔФ is the change in the magnetic flux, t is the time during which the change in the magnetic flux occurs. The “-” sign shows the direction of the induction current. ΔФ = Ф2 – Ф1. Let’s write Ohm’s law: I = E.D.S. / R. I = (Ф2 – Ф1) / R * t. According to the definition, the current strength is determined by the formula: I = Q / t, where Q is the amount of charge that passed through the conductor during time t. Q / t = (Ф2 – Ф1) / R * t. Q = (Ф2 – Ф1) / R. Q = (0.005 Wb – 0.002 Wb) / 3 Ohm = 0.001 Cl.
Answer: a charge Q = 0.001 C passed through the cross-section of the conductor.