A silver ingot with a volume of 70 cm has a mass of 135 g 1) what is the mass of a silver ingot

| July 7, 2021 | education

A silver ingot with a volume of 70 cm has a mass of 135 g 1) what is the mass of a silver ingot if its volume is 25 cm 2) what is the volume of a silver ingot weighing 420 g

70 cm ^ 3 – 135 g.

25 cm ^ 3 -? g.

Find the mass of 1 cm ^ 3 silver: 135: 70 = 135/70 = 27/14 grams.
Find the mass of a 25 cm ^ 3 silver bar: 27/14 * 25 = 675/14 = 48 3/14 grams.
Checking.

Find how many times the volume of the second silver ingot (25 cm ^ 3) is less than the volume of the first silver ingot (70 cm ^ 3): 70: 25 = 70/25 = 14/5 times, so many times and the mass is less.
Find the mass of a 25 cm ^ 3 silver bar: 135: 14/5 = (135 * 5) / 14 = 675/14 = 48 3/14 grams.
70 cm ^ 3 – 135 g.

? cm ^ 3 – 420 g.

Find the mass of 1 cm ^ 3 silver: 135: 70 = 135/70 = 27/14 grams.
Find the volume of a 420 gram silver bar: 420: 27/14 = 5880/27 = 217 7/9 (cm ^ 3).
Answer: 48 3/14 grams; 217 7/9 cm ^ 3.



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