A skater weighing 70 kg glides on the ice. What is the frictional force acting on a skater if the coefficient
| December 16, 2020 | education
A skater weighing 70 kg glides on the ice. What is the frictional force acting on a skater if the coefficient of friction of skates sliding on ice is 0.02?
The friction force is found according to the formula Ftr = k * N, where N = mg, now we simply substitute the values
Ftr = 0.02 * 70 * 10 = 14 (H)
Answer: Ftr = 14 (H)
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