A skier descends from a mountain in t = 20s, moves with an acceleration of a = 0.8 m / s squared, the initial speed

A skier descends from a mountain in t = 20s, moves with an acceleration of a = 0.8 m / s squared, the initial speed of the skier is V0 = 0. Determine: 1) v-speed of the skier at the end of the descent; 2) S-length of the descent

1) The speed at the end of the movement can be found by the formula U = U (initial) + at
U = 0 + 0.8 * 20 = 16m / s
2) also the path traveled with acceleration a can be found by the formula s = (U ^ 2 + U (zero) ^ 2) / 2a
S = 16 * 16/2 * 0.8 = 160 m