A skier rolls down the hill with a constant acceleration of 4 m / s2. What path will he cover in the third second?

Problem data: a (constant acceleration of a skier when rolling down a mountain) = 4 m / s2.

The path that the skier in question can cover in the third second of descent is calculated using the formula: S (3) = S3 – S2 = a * t3 ^ 2/2 – a * t2 ^ 2/2.

Let’s perform the calculation: S (3) = 4 * 3 ^ 2/2 – 4 * 2 ^ 2/2 = 18 – 8 = 10 m.

Answer: In the third second of descent from the mountain, the skier in question will cover a path of 10 meters.