A skier weighing 60 kg descended from a mountain 20 m high. What was the resistance to his movement

A skier weighing 60 kg descended from a mountain 20 m high. What was the resistance to his movement along the horizontal track after the descent, if he stopped after passing 200 m? Disregard friction.

m = 60 kg.

g = 10 N / kg.

h = 20 m.

S = 200 m.

Fsopr -?

When a skier descends from a mountain, his potential energy Ep goes to overcome the resistance force Fcopr, which performs negative mechanical work A: Ep = A.

We will express the potential energy of the skier En by the formula: En = m * g * h.

We express the mechanical work of the resistance force A by the formula: A = Fcopr * S.

m * g * h = Fcopr * S.

Fcopr = m * g * h / S.

Fcopr = 60 kg * 10 N / kg * 20 m / 200 m = 60 N.

Answer: on a horizontal track of the descent, the force of resistance to the movement of the skier is Fsopr = 60 N.