A slab weighing 2 tons is lifted from the bottom of the lake. what force must be applied if the volume

A slab weighing 2 tons is lifted from the bottom of the lake. what force must be applied if the volume of the slab is about, 5 m3?

The given tasks: m (mass of the slab, which is lifted from the bottom of the lake) = 2 tons (2 * 103 kg); V (volume of the lifted slab) = 0.5 m3.

Reference values: ρw (density of water in the lake) = 1000 kg / m3; g (acceleration due to gravity) ≈ 10 m / s2.

The force required to lift the slab from the bottom is determined by the formula: F = Ft – Fa = m * g – ρw * g * V = g * (m – ρw * V).

Calculation: F = 10 * (2 * 103 – 1000 * 0.5) = 10 * 1500 = 15,000 N (15 kN).

Answer: A force of 15 kN must be applied.