A sled with a mass of m = 50kg moves along a horizontal surface under the influence of a force F = 200N

| May 9, 2021 | education

A sled with a mass of m = 50kg moves along a horizontal surface under the influence of a force F = 200N directed at an angle a = 30 degrees to the horizon. what is the acceleration of the sleigh at the moment of the start of movement if the coefficient of friction of the sleigh on the snow layer is 0.1?

Data: m (sled weight) = 50 kg; F (acting force) = 200 N; α (angle between the direction of movement and the vector of the applied force) = 30º; μ (coefficient of friction against the snow layer) = 0.1; rectilinear movement.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

Projection of forces on the OX axis: m * a = F * cosα – Ftr. = F * cosα – μ * N = F * cosα – μ * (m * g – F * sinα), whence a = (F * cosα – μ * (m * g – F * sinα)) / m.

Calculation: a = (200 * cos 30º – 0.1 * (50 * 10 – 200 * sin 30º)) / 50 = 2.66 m / s2.



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