A sled with steel runners is moved on the ice evenly, applying a force of 2N.

A sled with steel runners is moved on the ice evenly, applying a force of 2N. Determine the weight of the sleigh if the coefficient of friction of steel on ice is 0.02.

F = 2 N.
g = 9.8 m / s ^ 2.
μ = 0.02.
m -?
According to Newton’s 1 law, sledges move evenly when the action of all forces on them is compensated.
The force F, with which the sled is pulled, is compensated by the friction force Ftr: F = Ftr.
The force of gravity m * g is compensated by the reaction force of the support N: m * g = N.
The friction force Ffr is determined by the formula: Ffr = μ * N
F = μ * m * g.
m = F / μ * g.
m = 2 N / 0.02 * 9.8 m / s ^ 2 = 10.2 kg.
Answer: the sled has a mass of m = 10.2 kg.



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