A small piston of a hydraulic press with an area of 200 cm2 is acted upon by a force of 100 N.

A small piston of a hydraulic press with an area of 200 cm2 is acted upon by a force of 100 N. What is the area of a large piston if oil presses on it with a force of 2 kN?

The operation of a hydraulic machine is described by the equation:
F1 / S1 = F2 / S2, where F1 and F2 are the forces acting on the pistons, S1 and S2, respectively, their area, using the above formula, we get:
S2 = F2 / F1 * S1
in a specific case, we get:
S2 = 2000/100 * 200 = 4000 cm ^ 2.