A small steel ball was thrown from the balcony vertically downward, giving it an initial velocity of 4 m / s.

A small steel ball was thrown from the balcony vertically downward, giving it an initial velocity of 4 m / s. From what height was the ball thrown if it reached the ground in 2 seconds?

Initial data: V (initial velocity with which the steel ball was thrown downwards) = 4 m / s; t (duration of the ball falling) = 2 s.

Reference values: g (acceleration due to gravity) = a (acceleration of a small steel ball) = 10 m / s2.

The height from which the ball was thrown will be equal to the distance traveled by it and is calculated by the formula: h = S = V0 * t + 0.5 * g * t ^ 2.

Let’s perform the calculation: h = 4 * 2 + 0.5 * 10 * 2 ^ 2 = 28 m.

Answer: A small steel ball was thrown from a height of 28 meters.