A small steel ball was thrown from the balcony vertically downward, giving it an initial velocity of 4 m / s. From what height was the ball thrown if it reached the ground in 2 seconds?
V0 = 4 m / s.
g = 9.8 m / s ^ 2.
t = 2 s.
The ball moves only under the action of gravity with the acceleration of gravity g, which is directed vertically downward. Since the initial velocity of the ball V0 is directed vertically downward and coincides with the direction of the gravitational acceleration g, the height of the ball throw h will be determined by the formula: h = V0 * t + g * t ^ 2/2.
h = 4 m / s * 2 s + 9.8 m / s ^ 2 * (2 s) ^ 2/2 = 27.6 m.
Answer: the height of the ball throw is h = 27.6 m.
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