A small weight of 500 g vibrates on a spring with a frequency of 5 Hz. Find the stiffness of the spring.

univerkov | December 19, 2020 | education

Given:
m = 500 g = 0.5 kg
V = 5 Hz
Find: k =?
Decision:
T = 1 / V
T = 1/5 = 0.2 s
T = 2n * \ / (m / k)
T ^ 2 = 2 ^ 2 * n ^ 2 * (m / k)
k = (4n ^ 2 * m) / T ^ 2
k = (4 * 3.14 ^ 2 * 0.5) / 0.2 ^ 2 = 493 N / m
Answer: k = 493 N / m

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