A snowball flying at a speed of 20 m / s hits the wall. What part of it will melt if the ambient temperature is 0 ْ С

A snowball flying at a speed of 20 m / s hits the wall. What part of it will melt if the ambient temperature is 0 ْ С, and all the kinetic energy is transferred to the snow.

To find the melted part of the snow after hitting the wall, we use the equality: Q = ΔEk; λ * m = mc * V ^ 2/2, whence we express: m / mc = V ^ 2 / 2λ.

Constants and variables: V – speed of the snow before hitting the wall (V = 20 m / s); λ – specific heat of melting of ice (λ = 3.4 * 10 ^ 5 J / kg).

Let’s perform the calculation: m / mc = V2 / 2λ = 20 ^ 2 / (2 * 3.4 * 10 ^ 5) = 400 / (6.8 * 10 ^ 5) = 1/1700.

Answer: After hitting the wall, 1/1700 of the thrown snow will melt.