A soccer ball weighing 0.4 kg falls to the ground from a height of 6 m and bounces to a height of 2.4 m.
| September 19, 2021 | education
A soccer ball weighing 0.4 kg falls to the ground from a height of 6 m and bounces to a height of 2.4 m. How much energy does the ball lose when it hits the ground?
To find the energy losses of a given soccer ball upon impact, we use the equality: Ep0 = Ep1 + Q, whence Q = Ep0 – Ep1 = m * g * (h0 – h1).
Constants and variables: m is the mass of a soccer ball (m = 0.4 kg); g – acceleration due to gravity (g ≈ 10 m / s2); h0 is the height of the soccer ball before it falls (h0 = 6 m); h1 – the height of the ball after bouncing (h1 = 2.4 m).
Calculation: Q = m * g * (h0 – h1) = 0.4 * 10 * (6 – 2.4) = 14.4 J.
Answer: When hitting the ground, the target soccer ball lost 14.4 Joules of energy.
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