A solution containing 14.6 g of hydrochloric acid was neutralized with an excess of calcium

A solution containing 14.6 g of hydrochloric acid was neutralized with an excess of calcium hydroxide, the amount of the formed salt is equal to …

Given:
m (HCl) = 14.6 g
Find:
n (CaCl2) =?
Solution:
1) Let’s compose the equation of the chemical reaction, let the amount of salt be x mol.
2HCl + Ca (OH) 2 = CaCl2 + 2H2O
2) Find the number of moles of hydrochloric acid.
n = m / M
M (HCl) = 1 + 35.5 = 36.5 g / mol
n (HCl) = 14.6 g: 36.5 g / mol = 0.4 mol.
3) 0.4 mol: 2 mol = x mol: 1 mol
x = (0.4 x 1): 2 = 0.2 mol.
Answer: n (CaCl2) = 0.2 mol.