A solution of 10% mass 100 g, acid 32% mass 50 g when mixing what percentage will be obtained.

Let’s find the total mass of pure acid in both solutions:

m (acid) = w1 (acid) * m (solution 1) + w2 (acid) * m (solution 2) = 0.1 * 100 + 0.32 * 50 = 26 g;

m (solution 3) = m (solution 1) + m (solution 2) = 100 + 50 = 150 g;

w3 (acid) = m (acid) / m (solution 3) = 26/150 = 0.1733 = 17.33%.

Answer: w3 (acids) = 17.33%.



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