A solution of barium chloride was added to 50 g of a 24% solution of magnesium sulfate.

A solution of barium chloride was added to 50 g of a 24% solution of magnesium sulfate. How many grams of sediment has formed?

Given:

m (MgSO4) = 50 g

w% (MgSO4) = 24%

Find:

m (draft) -?

Solution:

MgSO4 + BaCl2 = MgCl2 + BaSO4, – we solve the problem, relying on the composed reaction equation:

1) Find the mass of magnesium sulfate in solution:

m (MgSO4) = 50 g * 0.24 = 12 g

2) Find the amount of magnesium sulfate:

n (MgSO4) = m: M = 12 g: 120 g / mol = 0.1 mol

3) We compose a logical expression:

if 1 mol of MgSO4 gives 1 mol of BaSO4,

then 0.1 mol MgSO4 will give x mol BaSO4,

then x = 0.1 mol.

4) we find the mass of barium sulfate precipitated during the reaction:

m (BaSO4) = n * M = 0.1 mol * 233 g / mol = 23.3 g.

Answer: m (BaSO4) = 23.3 g.