A solution of barium chloride was added to a solution with a mass of 196 g with a mass fraction

A solution of barium chloride was added to a solution with a mass of 196 g with a mass fraction of sulfuric acid of 10%. Determine the mass of barium sulfate formed.

Barium chloride reacts with sulfuric acid. At the same time, a water-insoluble barium sulfate salt is synthesized, which precipitates. The reaction is described by the following chemical reaction equation.

BaCl2 + H2SO4 = BaSO4 + 2HCl;

Barium chloride reacts with sulfuric acid in equal molar amounts. This produces the same amount of insoluble barium sulfate.

Let’s calculate the chemical amount of sulfuric acid.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol; N H2SO4 = 196 x 0.10 / 98 = 0.2 mol;

The same amount of barium sulfate will be synthesized.

Let’s determine its weight.

M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol; m BaSO4 = 0.2 x 233 = 46.6 grams;