A solution of hydrochloric acid with a mass of 20 g with a mass fraction of a substance of 10%

A solution of hydrochloric acid with a mass of 20 g with a mass fraction of a substance of 10% reacted with calcium carbonate. How much gas will be released?

Given:
m solution (HCl) = 20 g
w (HCl) = 10% = 0.1
To find:
V (CO2)
Decision:
CaCO3 + 2HCl = CaCl2 + H2O + CO2
m in islands (HCl) = w * m solution = 0.1 * 20 g = 2 g
n (HCl) = m / M = 2 g / 36.5 g / mol = 0.05 mol
n (HCl): n (CO2) = 2: 1
n (CO2) = 0.05 mol / 2 = 0.025 mol
V (CO2) = n * Vm = 0.025 mol * 22.4 l / mol = 0.56 l
Answer: 0.56 L