A solution of lead oxide 2 with a mass of 701 g and a mass fraction of a substance of 38%, upon interaction with carbon monoxide

A solution of lead oxide 2 with a mass of 701 g and a mass fraction of a substance of 38%, upon interaction with carbon monoxide, formed carbon dioxide, the volume of which must be found.

Let’s compose the reaction equation: PbO + CO = Pb + CO2.
Let’s calculate the mass of the substance PbO: 701 * 0.38 = 266.38 (g).
Let’s calculate the amount of lead oxide substance: 266.38 / 223 = 1.2 (mol).
The amount of carbon dioxide will be equal to the amount of carbon dioxide according to the reaction equation.
The volume of carbon dioxide will be equal to: 1.2 * 22.4 = 26.88 (l).