A solution of magnesium nitrate weighing 400 g with a mass fraction of salt of 22.2% was mixed with a solution

A solution of magnesium nitrate weighing 400 g with a mass fraction of salt of 22.2% was mixed with a solution of potassium orthophosphates weighing 205 g and a mass fraction of salt of 42.4%. Calculate and indicate the mass of sediment in grams

Given:
m solution (Mg (NO3) 2) = 400 g
ω (Mg (NO3) 2) = 22.2%
m solution (K3PO4) = 205 g
ω (K3PO4) = 42.4%

Find:
m (draft) -?

Solution:
1) 3Mg (NO3) 2 + 2 K3PO4 => Mg3 (PO4) 2 ↓ + 6KNO3;
2) m (Mg (NO3) 2) = ω * m solution / 100% = 22.2% * 400/100% = 88.8 g;
3) n (Mg (NO3) 2) = m / M = 88.8 / 148 = 0.6 mol;
4) m (K3PO4) = ω * m solution / 100% = 42.4% * 205/100% = 86.92 g;
5) n (K3PO4) = m / M = 86.92 / 212 = 0.41 mol;
6) n (Mg3 (PO4) 2) = n (Mg (NO3) 2) / 3 = 0.6 / 3 = 0.2 mol;
7) m (Mg3 (PO4) 2) = n * M = 0.2 * 262 = 52.4 g.

Answer: The mass of Mg3 (PO4) 2 is 52.4 g.