A solution of phosphate K was added to 188.8 g of Ca chloride solution with a mass fraction of 25%

| August 7, 2021 | education

A solution of phosphate K was added to 188.8 g of Ca chloride solution with a mass fraction of 25%. Find the mass of the precipitate.

The mass of calcium chloride is 188.8 g.

Mass fraction of calcium chloride – 25%.

Determine the mass fraction of the resulting sediment.

First, you need to write down the reaction equation.

3СаCl2 + 2K3PO4 = Ca3 (PO4) 2 + 6KCl.

First you need to calculate the mass of calcium chloride. Let’s write down the formula needed for calculations.

W = m r.v / m r-ra * 100%.

Let’s determine the mass of the soluble substance.

m r.h. = 188.8 * 0.25 = 47.2 g.

Next, you need to calculate the molar mass of calcium chloride and calcium phosphate.

M (CaCl2) = 111 g / mol.

M (Ca3 (PO4) 2) = 310 g / mol.

47.2 g – x g

3 * 111 g / mol – 310 g / mol.

X = 310 * 47.2 / 333 = 43.9 g.

Answer: the mass of the sediment obtained is 43.9 g.



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