A solution of salted ox with a mass of 600 g with a concentration of 15% was added a solution of salt water with a mass of 240 g

A solution of salted ox with a mass of 600 g with a concentration of 15% was added a solution of salt water with a mass of 240 g with a concentration of 50%. What is the percentage of salt in the mixture? 1. How many grams of salt are in 1 solution? 2. How many grams of salt are in 2 solution? 3. What is the total mass of the mixture prepared from the two solutions?

1. Determine the mass of salt in the first solution. We take this mass as a and make up the proportion:
600 g – 100%, and g – 15%;
600: a = 100: 15;
a = (600 x 15): 100;
a = 90 g;
2. Determine the mass of salt in the second solution. We take this mass as a and make up the proportion:
240 g – 100%, and g – 50%;
240: a = 100: 50;
a = (240 x 50): 100;
a = 120 g;
3. Determine the mass of salt in the new solution:
90 + 120 = 210 g;
4. Determine the mass of the new solution:
600 + 240 = 840 g;
5. Determine the salt concentration in the new mixture. We take it for a and make up the proportion:
840 g – 100%, 210 g – a%;
840: 210 = 100: a;
a = (210 x 100): 840;
a = 25%.
Answer: 25% is the salt concentration in the new solution; 90 grams of salt in the first solution; 120 grams of salt in the second solution; 840 grams is the mass of the new mixture.



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