A solution of soda weighing 212 grams with a mass fraction of sodium carbonate 10% was treated

A solution of soda weighing 212 grams with a mass fraction of sodium carbonate 10% was treated with hydrochloric acid in a stoichiometric ratio. Find the volume of carbon dioxide.

Let’s write the reaction equation:

Na2CO3 + 2HCl = 2NaCl + CO2 ↑ + H2O

Let’s find the mass of Na2CO3 in solution:

m (Na2CO3) = mr.-pa (Na2CO3) * w (Na2CO3) / 100 = 212 * 10/100 = 21.2 (g).

Let’s find the amount of the substance Na2CO3:

v (Na2CO3) = m (Na2CO3) / M (Na2CO3) = 21.2 / 106 = 0.2 (mol).

According to the reaction equation, 1 mol of CO2 is formed from 1 mol of Na2CO3, therefore:

v (CO2) = v (Na2CO3) = 0.2 (mol).

Thus, the volume of emitted carbon dioxide, measured under normal conditions (n.o.):

V (CO2) = v (CO2) * Vm = 0.2 * 22.4 = 4.48 (l).

Answer: 4.48 l.