A solution of sodium chloride weighing 29.25 g, with a mass fraction of salt of 20%, was mixed with a solution

A solution of sodium chloride weighing 29.25 g, with a mass fraction of salt of 20%, was mixed with a solution of argentum nitrate weighing 117 g with a mass fraction of salt of 16%. Report the mass of sediment (in grams) that is formed during this.

Given:
m solution (NaCl) = 29.25 g
ω (NaCl) = 20%
m solution (AgNO3) = 117 g
ω (AgNO3) = 16%

To find:
m (draft) -?

Solution:
1) NaCl + AgNO3 => AgCl ↓ + NaNO3;
2) m (NaCl) = ω (NaCl) * m solution (NaCl) / 100% = 20% * 29.25 / 100% = 5.85 g;
3) n (NaCl) = m (NaCl) / M (NaCl) = 5.85 / 58.5 = 0.1 mol;
4) m (AgNO3) = ω (AgNO3) * m solution (AgNO3) / 100% = 16% * 117/100% = 18.72 g;
5) n (AgNO3) = m (AgNO3) / M (AgNO3) = 18.72 / 170 = 0.11 mol;
6) n (AgCl) = n (NaCl) = 0.1 mol;
7) m (AgCl) = n (AgCl) * M (AgCl) = 0.1 * 143.5 = 14.35 g.

Answer: The mass of AgCl is 14.35 g.