A spacecraft weighing 10 ^ 6kg begins to rise vertically upward. The thrust force of its engines is 2.94 * 10 ^ 7 N.

| January 3, 2021 | education

A spacecraft weighing 10 ^ 6kg begins to rise vertically upward. The thrust force of its engines is 2.94 * 10 ^ 7 N. Determine the acceleration of the ship and the weight of the body in it, if the gravity force on the Earth is 5.88 * 10 ^ 2N.

Data: mk is the mass of the spacecraft (mk = 106 kg); Ftyag is the thrust force of the engines of the presented spacecraft (Ftyag = 2.94 * 10 ^ 7 N); Fтт – the force of gravity acting on a body in a ship on Earth (Fтз = 5.88 * 10 ^ 2 N); air resistance is not taken into account.
Const: g – acceleration due to gravity (g ≈ 9.8 m / s2).
1) Acceleration of the presented spacecraft: mk * a = Ftyag – Ftk = Ftyag – mk * g, whence we express: a = (Ftyag – mk * g) / mk.
Calculation: a = (Ftyag – mk * g) / mk = (2.94 * 10 ^ 7 – 10 ^ 6 * 9.8) / 10 ^ 6 = 19.6 m / s2.
2) Body weight in the ship: Pt = mt * a + Ftz = Ftz * a / g + Ftz = Ftz * (a / g + 1).
Calculation: Pt = Ftz * (a / g + 1) = 5.88 * 10 ^ 2 * (19.6 / 9.8 + 1) = 1764 N.
Answer: The acceleration of the presented spacecraft is 19.6 m / s2; the body weight in the ship will be 1764 N.



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