A sports car, moving along a trajectory in the form of a circle R = 600m, makes 1 revolution in a time t = 1min.

A sports car, moving along a trajectory in the form of a circle R = 600m, makes 1 revolution in a time t = 1min. Determine: 1) the movement r of the car in t = 1 min; 2) The path S covered by the car in t = 1 min; 3) the average speed of the car v for 1 min; 4) The average ground speed of the car Vs for t = 1 min.

R = 600 m.

n = 1.

t = 1 min = 60 s.

S -?

L -?

Vсрs -?

Vсрl -?

The time T, during which the car makes one complete revolution, is called the rotation period.

The traversed path L is the length of the line that the body describes when moving.

The car travels the path L equal to the circumference of the radius R: L = 2 * P * R.

L = 2 * 3.14 * 600 m = 3768 m.

The displacement S is called the vector that connects the starting and ending positions of the body. When the car made a full revolution, it returned to its original position, so S = 0.

Average ground speed Vсрl is determined by the formula: Vсрl = L / t.

Vavl = 3768 m / 60 s = 62.8 m / s.

The average speed of displacement Vavs is determined by the formula: Vavs = S / t.

Vavs = 0 m / s.

Answer: L = 3768 m, S = 0, Vavl = 62.8 m / s, Vavs = 0 m / s.