A sports car moving uniformly along a trajectory in the form of a circle with a radius of 600 m

A sports car moving uniformly along a trajectory in the form of a circle with a radius of 600 m, made one revolution in 1 min. Determine 1) the distance traveled by the car in 1 min 2) the average speed of the car in 0.5 min

R = 600 m.

T = 1 min = 60 s.

t1 = 0.5 min = 30 s.

L -?

Vav -?

The traversed path L is the length of the trajectory that the body describes when moving.

In one complete revolution, a sports car travels a path L equal to the circumference of a radius R.

The circumference of the circle is expressed by the formula: L = 2 * P * R, where P is the number pi, R is the radius of the circle.

L = 2 * 3.14 * 600 m = 3768 m.

To find the average vehicle speed Vav, it is necessary to divide the entire path L traveled by the time of its passage t along the entire path: Vav = L / T.

Since the car moves uniformly, then during the movement t1 = 30 s, it will travel half a circle: L1 = L / 2.

Vav = L1 / t1 = L / 2 * t1 = 2 * P * R / 2 * t1 = P * R / t1.

Vav = 3.14 * 600 m / 30 s = 62.8 m / s

Answer: the path of the sports car was L = 3768 m, the average movement speed Vc = 62.8 m / s.