A spring 15 cm long is stretched with a force of 30 N. With a spring stiffness k = 103 N / m, its final length is …
| December 1, 2020 | education
Given: x1 = 15cm = 0.15m
F = 30H
k = 103 N / m
Find: x2-?
F = k * ∆x
∆x = x2-x1
F = k * x2-k * x1
k * x2 = F + k * x1
x2 = (F + k * x1): k
x2 = (30N + 103n / m * 0.15m): 103n / m
x2 ~ 0.5m
Answer: 0.5m
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