A spring compressed by 2 cm throws the steel ball vertically upwards by 20 cm. How much will the flight

| September 6, 2021 | education

A spring compressed by 2 cm throws the steel ball vertically upwards by 20 cm. How much will the flight height of the ball increase when the spring is compressed by 4 cm, if all the energy of the compressed spring is transferred to the ball?

Data: Δх1 (first compression) = 2 cm = 0.02 m; h1 (the first height of the ball rise) = 20 cm = 0.2 m; Δx2 (second compression) = 4 cm = 0.04 m.

We transform the law of conservation of energy: k * Δx ^ 2/2 = m * g * h, whence 2 * m * g / k = Δx2 / h.

The resulting equality: Δx1 ^ 2 / h1 = Δx2 ^ 2 / h2, whence h2 = Δx2 ^ 2 * h1 / Δx1 ^ 2.

Second lifting height: h2 = 0.04 ^ 2 * 0.2 / 0.02 ^ 2 = 0.8 m = 80 cm.

Increase in lifting height: Δh = h2 – h1 = 80 – 20 = 60 cm.

Answer: The lifting height will increase by 60 cm.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.