A spring-loaded pendulum with a spring rate of 200 Nm performs harmonic oscillations. at some point, its kinetic energy is 10 J, and the potential energy is 15 J. What will be the amplitude of the fluctuations
These tasks: k (rigidity of the used spring pendulum) = 200 N / m; Ek (kinetic energy at some point in time) = 10 J; Ep (potential energy at some point in time) = 15 J.
1) The total energy of the used spring pendulum: E = Ek + Ep = 10 + 15 = 25 J.
2) Determine the amplitude of oscillations: E = k * A ^ 2/2, whence A = √ (2 * E / k) = √ (2 * 25/200) = 0.5 m.
Answer: The amplitude of oscillation of the used spring pendulum is 0.5 m.
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