A spring with a stiffness factor of 1000 is acted upon by a force of 40 Newtons. Find the potential energy of the spring.
| November 17, 2020 | education
F (elastic force) = k (spring stiffness) * Δх
Δх = F: k
Δх = 40: 1000
Δх = 0.04m
Ep = k * Δx ^ 2
En = (1000 * (0.04) ^ 2): 2
Ep = (1000 * 0.0016): 3
Ep = 1.6: 2
Ep = 0.8
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