A spring with a stiffness factor of 5 N / m, compressed by 7 cm, has energy?

univerkov | August 7, 2021 | education

Initial data: k (coefficient of stiffness of a compressed spring) = 5 N / m; Δl (value of compression (deformation) of the spring) = 7 cm.

SI system: Δl = 7 cm = 7/100 m = 0.07 m.

The potential energy of a given spring can be calculated using the following formula: En = k * Δl ^ 2/2.

Let’s do the calculation:

Ep = 5 * 0.07 ^ 2/2 = 0.01225 J = 12.25 * 10 ^ -3 J = 12.25 mJ.

Answer: The potential energy of this spring is 12.25 mJ.

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