A spring with a stiffness of 1000 N / m in an undeformed state has a length of 0.25 m. What is the length
| December 3, 2020 | education
A spring with a stiffness of 1000 N / m in an undeformed state has a length of 0.25 m. What is the length of the spring if a weight of 2 kg is suspended from it?
Given: k = 1000 H / m l = 0.25 m m = 2 kg g = 10 m / s ^ 2
Find: L-?
Solution: k * x = m * g => x = (m * g) / k = (2 * 10) / 1000 = 0.02 (m) L = l + x = 0.25 + 0.02 = 0 , 27 (m)
Answer: 0.27 m.
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