A spring with a stiffness of 40 N / m is stretched with a force of 2 N. How much will the spring lengthen?

Given:
k = 40 Newton / meter – coefficient of spring stiffness;
F = 2 Newtons – the force with which the spring is stretched.
It is required to determine the value of the spring extension dx (meter).
To find the amount of spring elongation, you must use the following formula (Hooke’s law):
F = k * dx, hence:
dx = F / k = 2/40 = 0.05 meters (5 centimeters).
Answer: The spring will lengthen 0.05 meters (5 centimeters).