A spring without load, hanging vertically, has a length L0 = 10 cm, if a load weighing 0.5 kg

A spring without load, hanging vertically, has a length L0 = 10 cm, if a load weighing 0.5 kg is suspended on it, its length becomes. L1 = 15 cm, determine the spring stiffness from these long L0

Data: L0 (unloaded spring length) = 10 cm = 0.1 m; m (weight of the suspended load) = 0.5 kg; L1 (spring length under load) = 15 cm = 0.15 m.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

To determine the stiffness of the spring taken, we use the equality: F = Fcont and m * g = k * Δx = k * (L1 – L0), whence k = m * g / (L1 – L0).

Calculation: k = 0.5 * 10 / (0.15 – 0.1) = 100 N / m.

Answer: The stiffness of the spring taken is 100 N / m.