A square with a side of 9√2 is inscribed in a circle. Find the side of a regular triangle circumscribed about this circle.
May 20, 2021 | education
| Construct the diagonal MP of the square, which will be the diagonal of the square described around it.
The triangle KMP is rectangular, then, by the Pythagorean theorem, MP ^ 2 = 2 * KM ^ 2 = 2 * (9 * √2) ^ 2 = 324.
MP = 18 cm.
Then the radius of the circle is: R = MP / 2 = 18/2 = 9 cm.
The radius of a circle inscribed in an equilateral triangle is:
R = AB * √3 / 6, then AB = 6 * R / √3 = 6 * 9 / √3 = 54 / √3 = 18 * √3 cm.
Answer: The side of the triangle is 18 * √3 cm.
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