A stationary body weighing 100 kg for 2 s was acted upon by a force of 5 N. How far did the body move?

These tasks: the body was motionless and V0 (initial velocity) = 0 m / s; m (body weight) = 100 kg; t (duration of action of the force on the body) = 2 s; F (acting force) = 5 N.
The distance that the body moved under the action of a given force is determined by the formula: S = 0.5 * a * t ^ 2 = 0.5 * (F / m) * t ^ 2.
Calculation: S = 0.5 * (5/100) * 2 ^ 2 = 0.1 m (10 cm).
Answer: The body, under the action of a force of 2 N, has moved 10 centimeters.