A steel ball weighing 50 g freely falls from a height of 15 m. What is the kinetic energy

A steel ball weighing 50 g freely falls from a height of 15 m. What is the kinetic energy of the ball at a height of 5 m from the earth’s surface?

To find the kinetic energy of a steel ball at a given height, we will use the formula: Ek = Ep1 – Ep2 = m * g * h1 – m * g * h2 = m * g * (h1 – h2).

Constants and variables: m is the mass of the steel ball (m = 50 g = 0.05 kg); g – acceleration due to gravity (g ≈ 10 m / s2); h1 – initial height of the ball (h1 = 15 m); h2 – considered height (h2 = 5 m).

Let’s perform the calculation: Ek = m * g * (h1 – h2) = 0.05 * 10 * (15 – 5) = 5 J.

Answer: At a height of 5 m from the surface, the kinetic energy of the steel ball will be 5 J.