A steel cutter weighing 2 kg was heated to a temperature of 800 degrees C

| April 9, 2021 | education

A steel cutter weighing 2 kg was heated to a temperature of 800 degrees C and then lowered into a vessel containing 15 liters of water at a temperature of 10 degrees C. To what temperature will the water in the vessel be heated?

Given: m1 (weight of the steel cutter) = 2 kg; t1 (temperature of the cutter before immersion in water) = 800 ºС; V (volume of water) = 15 l (m2 (mass of water) = 15 kg); t2 (water temperature) = 10 ºС.

Constants: Cc (specific heat capacity of steel) = 500 J / (kg * K); Cw (specific heat capacity of water) = 4200 J / (kg * K).

The temperature of the water in the vessel after the immersion of the cutter is determined from the equality: Cc * m1 * (t1 – t) = Cw * m2 * (t – t2).

500 * 2 * (800 – t) = 4200 * 15 * (t – 10).

800000 – 1000t = 63000t – 630000.

64000t = 1430000.

t = 22.34 ºС.



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