A steel part weighing 300 g, heated to 300 ° C, was thrown into water weighing 5 kg at a temperature of 20 ° C.

A steel part weighing 300 g, heated to 300 ° C, was thrown into water weighing 5 kg at a temperature of 20 ° C. How many degrees did the water temperature rise if all the energy released by the part was used to heat the water?

Solution:
0.3 * 500 * (300-Ttr) = 5 * 4200 * (Ttr-20)
150 (300-Ttr) = 21000 (Ttr-20)
45000-150 Ttr = 21000 / Ttr-420000
465000 = 21150Ttr
Ttr = 22 ° C
Ttr-t2 = 22-20 = 2 ° C
Answer: 2 ° C